Question

Simplify:- 4ax [16b+4-6[a-(4b-2a)]]

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Answer 1

Answer:

$-256a^{2}b^{2}x$ +$128a^{3}bx$ - $32a^{2}bx$+$16a^{3}bx$

Step-by-step explanation:

= 4ax [16b+4-6[a-(4b-2a)]]

= 4ax [16b+4-6[-4ab+$2a^{2}$]]

= 4ax[16b-2[-4ab+$2a^{2}$]]

=4ax[-$64ab^{2}$+32$a^{2}b$]-[8ab-$4a^{2}$]

= 4ax[-$64ab^{2}$+32$a^{2}b$-8ab+$4a^{2}$]

= $-256a^{2}b^{2}x$ +$128a^{3}bx$ - $32a^{2}bx$+$16a^{3}bx$

= tried my best.. hope it helps you

Answer 2

Answer:

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