Question

simplify:
4st(s-t)-6s^2(t-t)-3t^2(2s^2-s)+2st(s-t)

Answer 1

Given:

Given expression is: $4st(s-t)-6s^2(t-t)-3t^2(2s^2-s)+2st(s-t)$

To find:

We need to simplify the given expression.

Solution:

The given expression is,

$4st(s-t)-6s^2(t-t)-3t^2(2s^2-s)+2st(s-t)$

First, multiply the terms with the terms present in parenthesis ().

$\Rightarrow 4st\times s+4st\times (-t)-6{{s}^{2}}\times t-6{{s}^{2}}\times (-t)-3{{t}^{2}}\times 2{{s}^{2}}-3{{t}^{2}}\times (-s)+2st\times s+2st\times (-t)$

$\Rightarrow 4{{s}^{2}}t-4s{{t}^{2}}-6{{s}^{2}}t+6{{s}^{2}}t-6{{t}^{2}}{{s}^{2}}+3s{{t}^{2}}+2{{s}^{2}}t-2s{{t}^{2}}$

$\Rightarrow 4{{s}^{2}}t-4s{{t}^{2}}-6{{t}^{2}}{{s}^{2}}+3s{{t}^{2}}+2{{s}^{2}}t-2s{{t}^{2}}$

Now, write similar terms together.

$\Rightarrow 4{{s}^{2}}t+2{{s}^{2}}t-4s{{t}^{2}}+3s{{t}^{2}}-2s{{t}^{2}}-6{{t}^{2}}{{s}^{2}}$

$\Rightarrow 6{{s}^{2}}t-3s{{t}^{2}}-6{{t}^{2}}{{s}^{2}}$

Taking $3$ as common,

$& \Rightarrow 3(2{{s}^{2}}t-s{{t}^{2}}-2{{t}^{2}}{{s}^{2}})$

Taking $st$ as common,

$\Rightarrow 3st(2s-t-2ts)$

Therefore, after simplification, the answer is $3st(2s-t-2ts)$.

Answer 2

Answer:

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