Question

simplify (4x^2 +7x-1) -(x^2+8x-7) +(x^2+10)​

Answer 1

$\underline\red{\underline{\sf{\maltese\: Solution\::-}}}$

$\sf{(4 x^{2} + 7x - 1) - ( {x}^{2} + 8x - 7) + ( {x}^{2} + 10)}$

~$\sf{{4x}^{2} + 7x - 1 - {x}^{2} - 8x + 7 + {x}^{2} + 10}$

~$\sf{{4x}^{2} - {x}^{2} + {x}^{2} + 7x - 8x - 1 + 7 + 10}$

~$\sf{{4x}^{2} - x + 16}$

Answer 2

Answer:

The answer is $4x^2-x+16$.

Step-by-step explanation:

Given,

$(4x^{2} + 7x-1) - (x^2 +8x-7) + (x^2+10)$

We need to add the given equation to get the final answer. Basically, We add the coefficients of each term with same exponent in given equation to get the final equation.

So we add the coefficient of the highest exponent first.

Coefficient of $x^2 =$ 4 - 1 + 1 = 4

Coefficient of $x^1 =$ 7 - 8 = -1

Coefficient of $x^0 =$ -1 + 7 + 10= 16

The Final equation will result as $4x^2-x+16$

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