Question

Simplify 4y( 2y – 7 ) – 5 and find its value for y = – 1
please help me fast​

Answer 1

Answer:

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Step-by-step explanation:

$4y( 2y - 7 ) - 5 \\ \\ 8 {y}^{2} - 28y -5 \\ \\ putting \: \: y = - 1 \\ \\ 8 {( - 1)}^{2} - 28( - 1) - 5\\ \\ 8(1) + 28 - 5 \\ \\ 8 + 28 - 5 \\ \\ 31$

Answer 2

Step-by-step explanation:

8y^2–28y–5

if y = –1

then

8(-1)^2–28(-1)–5

=8+28–5

=36–5

=31