simplify : (√5-√3)²
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I will interpret your question as “what is the value of (-1-i*sqrt(3))^2?”
Sorry if the notation is ugly, I dont know how to use special chars and I am too lazy look it up
Using (a+b)^2=a^2+b^2+2ab
x ^2= (-1-i*sqrt(3))^2 = (1+i*sqrt(3))^2 = 1 - 3 +2i*sqrt(3) = 2 * (i*sqrt(3)-1). That is an analytical awnser, but a boring one.
|(-1-i*sqrt(3))| = sqrt(4) = 2 [using pythagoras]
arg(-1-i*sqrt(3)) = arctan(-sqrt(3)/-1)=60 degrees = pi/3 radians
using euler’s identity: x = |x|e^(i*arg(x))
x = 2*e^(i*pi/3)
since: |x^2| = |x|^2 = 4 and arg(x^2) = 2*arg(x) = 2*pi/3
Then:
x^2 = 4*e^(2*i*pi/3)
I hope it was useful
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Pls mark me as Brainliest thank you
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