Math, asked by sreevishnu77, 1 year ago

simplify:(5/7)^3×(5/7)^-5 the answer should be in positive exponent

Answers

Answered by TooFree
6

\bigg(\dfrac{5}{7} \bigg)^3 \times \bigg( \dfrac{5}{7} \bigg)^{-5}

= \dfrac{5^3}{7^3} \times \dfrac{5^{-5}}{7^{-5}}

= \dfrac{5^3}{7^3} \times \dfrac{7^{5}}{5^{5}}

= \dfrac{5^3 \times 7^5 }{7^3 \times 5^5}

=5^{3-5} \times 7^{5-3}

= 5^{-2} \times 7^{2}

= \dfrac{7^2}{5^2}

= \bigg( \dfrac{7}{5} \bigg)^2


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Answered by duragpalsingh
1
Hey there!

Solution is enclosed!

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