Simplify: (- √5- √7) by (√2- 3)
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√Given (3√5-√7)/(3√3 + √2)
=[(3√5-√7)(3√3-√2)]/[(3√3+√2)(3√3-√2)]
=[9√15-3√10-3√21+√14]/[(3√3)²-(√2)²]
[ Since x²-y² =(x+y)(x-y)]
=[9√15-3√10-3√21+√14]/(27-2)
= (9√15-3√10-3√21+√14)/25
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Answer:
(- √5- √7) ÷(√2- 3)
multiplying the conjugate on the numerator and the denominator
= (- √5- √7)(√2+ 3) /(√2- 3) (√2+ 3)
= (- √5- √7)(√2+ 3) /( 2-3²)
= (-√10 -3√5 -√14 -3√7 )/-7
= 1/7 (√10 +3√5 +√14 +3√7 ) (answer)
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