Math, asked by pramit65, 10 months ago

simplify:(5x+2y)^2-(2x+5y)^2.​

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Answered by Nitishpandeyji
2

Answer:

(5x+2y)^2-(2x+5y)^2

let use the formulae of (a+b)^2=a^2+b^2+2ab

<(5x)^2+(2y)^2+2*5x*2y> -<2x^2+5y^2+2*2x*5y>

<25x^2+4y^2+20xy>-<4x^2+25y^2+20xy>

25x^2+4y^2+20xy-4x^2-25y^2-20xy

25x^2-4x^2+4y^2-25y^2+20xy-20xy

21x^2-21y^2=0

take 21 common

21(x^2+y^2)=0 then,

x^2+y^2=0

Step-by-step explanation:

Answered by geetgupta1
1

Step-by-step explanation:

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