Question

simplify √6/√2+√3+3√2/√6+√3-4√3/√6+√2

pls answers

challenge for all brainliests...❎❎❎❎

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Answer 1

Conjugate of a first term (√2+√3) is

(√2-√3)

Conjugate of second term (√6+√3) is (√6-√3)

Conjugate of third term (√6+√2) is (√6-√2)

In denominator FORMULA used=

(a+b)(a-b)= a² - b²


Hope It helps you