Math, asked by mohammedminhaal625, 8 months ago

Simplify:
√6/√2+√3+3√2/√6+√3-4√3/√6+√2

step by step explanation

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Answers

Answered by SandeepAW
0

Answer:

√6/√2+√3+3√2/√6+√3-4√3/√6+√2.

√2+√3 is √2-√3.

√6+√3 is √6-√3.

√6+√2 is √6-√2.

Multiply numerator & denominator by √2-√3, √6-√3 & √6-√2.

(√6/√2+√3×√2-√3/√2-√3)+(3√2/√6+√3×√6-√3/√6-√3)-(4√3/√6+√2×√6-√2/√6-√2).

(√6(√2-√3)/(√2)²-(√3)²)+(3√2(√6-√3)/(√6)²-(√3)²)-(4√3(√6-√2/(√6)²-(√2)²).

(√6(√2-√3)/2-3)+(3√2(√6-√3)/6-3)-(4√3(√6-√2)/6-2).

(√6(√2-√3)/-1)+(3√2(√6-√3)/3)-(4√3(√6-√2/4).

√6(√2-√3)+√2(√6-√3)-√3(√6-√2).

I think this is your answer.

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