Question

simplify 6-4√3/6+4√3 by rationalising the denominator.

Answer 1

(6-4_/3)/(6+4_/3)
=(6-4_/3)^2/(6^2-(4_/3)^2)
(multiplied by (6-4_/3) on numerator and denominator)
=(36+48-48_/3)/(36-48)
=(84-48_/3)/(-12)
=4_/3 - 7 (divided by (-12))

PLZ MARK IT AS BRAINLIEST..

Answer 2

6-4√3/6+4√3

Rationalising factor = 6-4√3

=(6-4√3)/(6+4√3)×(6-4√3)/(6-4√3)

=(6-4√3)(6-4√3)/(6+4√3)(6-4√3)

=(6-4√3)²/(6²-(4√3)²)

=[6²+(4√3)²-2(6)(4√3)]/(36-16(3))

=[36+16(3)-48√3]/(36-48)

=[36+48-48√3]/(-12)

= -(84-48√3)/12

=(-84+48√3)/12

=(-84/12)+(48√3)/12

= -7+4√3

Hope it helps