Question

simplify (6+root 27)-(3+root3)+(1-2root3)

Answer 1

Step-by-step explanation:

$(6 + \sqrt{27} ) -( 3 + \sqrt{3} )(1 - 2 \sqrt{3} )$

$6 + 3 \sqrt{3} - 3 + \sqrt{3} + 1 -2 \sqrt{3}$

$7 - 3 + 3 \sqrt{3} - 3 \sqrt{3}$

$= 4$

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Answer 2

Answer:

$(6 + \sqrt{27} ) - (3 + \sqrt{3} ) + (1 - \sqrt[2]{3} )$

Solve the roots in simpler form,

=6 + 3\sqrt{3}- 3-\sqrt{3}+1 - 2\sqrt{3}=6+3

3

−3−

3

+1−2

3

Solve like terms,

=4+\sqrt{3}(3-1-2)=4+

3

(3−1−2)

=4+\sqrt{3}(0)=4+

3

(0)

=4=4

Therefore, (6 + \sqrt{27}) - (3 + \sqrt{3}) + (1 - 2\sqrt{3})=4(6+

27

)−(3+

3

)+(1−2

3

)=4