Math, asked by sonnali7642, 10 months ago

Simplify 6 upon 2 root 3 minus root 6 plus root 6 upon root 3 plus root 2 minus 4 root 3 upon root 6 minus root 2

Answers

Answered by Anonymous
125

Step-by-step explanation:

(•‿•) hope it's helpful

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Answered by TanikaWaddle
99

Given : \frac{6}{2\sqrt{3}-\sqrt{6}}+\frac{\sqrt{6}}{\sqrt{3}+\sqrt{2}}- \frac{4\sqrt{3}}{\sqrt{6}-\sqrt{2}}

Step-by-step explanation:

\frac{6}{2\sqrt{3}-\sqrt{6}}+\frac{\sqrt{6}}{\sqrt{3}+\sqrt{2}}- \frac{4\sqrt{3}}{\sqrt{6}-\sqrt{2}}\\\\rationalizing\\\\\frac{6}{2\sqrt{3}-\sqrt{6}}\times \frac{2\sqrt{3}+\sqrt{6}}{2\sqrt{3}-\sqrt{6}}+\frac{\sqrt{6}}{\sqrt{3}+\sqrt{2}}\times \frac{\sqrt{3}-\sqrt{2}}{\sqrt{3}+\sqrt{2}}-\frac{4\sqrt{3}}{\sqrt{6}-\sqrt{2}}\times \frac{\sqrt{6}+\sqrt{2}}{\sqrt{6}+\sqrt{2}}

\frac{12\sqrt{3}+6\sqrt{6}}{12-6}+\frac{\sqrt{18}-\sqrt{12}}{3-2}-\frac{4\sqrt{18}+4\sqrt{2}}{6-2}\\\\\frac{6\sqrt{6}}{2}+\sqrt{18}- \sqrt{12}- 2\sqrt{2}\\\\\text{taking LCM }\\\\\frac{3\sqrt{6}+6\sqrt{2}-2\sqrt{12}-4\sqrt{2}}{2}\\\\\frac{3\sqrt{6}+2\sqrt{2}-4\sqrt{3}}{2}

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https://brainly.in/question/12458396

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