simplify 6 upon 3√2+2√3
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Answer:
Solution is in theAttachment.
First rationalize the denominator of each term by multiplying its conjugate in both the numerator and denominator and simplify it.
Conjugate of a first term (√2+√3) is
(√2-√3)
Conjugate of second term (√6+√3) is (√6-√3)
Conjugate of third term (√6+√2) is (√6-√2)
In denominator FORMULA used=
(a+b)(a-b)= a² - b²
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Answered by
0
Answer:
As a result we will be adding our first term in our products
The answer will be 3(73√43)
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