simplify:(64/125)^-2/3+(625/256)^1/4+25/3√64.
vickySingh111:
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Answered by
58
(64/125)^(-2/3) + (625/256)^1/4 + 25/3Root64
We know that,
64 = 4^3
125 = 5^3
625= 5^4
256 = 4^4
root 64 = 8
Substitute these values:
(4^3/5^3)(-2/3) + (5^4/4^4)^1/4 + 25/3*8
(4/5)^(-2) + (5/4) + 25/24
(5/4)^2 + 5/4 + 25/24
25/16 + 5/4 + 25/24
5/4* [ 5/4 + 1 + 5/6] = 5/4*[15+12+10/12]
= 5/4 * 37/12 = 185/48 = 3.85 (approx)
We know that,
64 = 4^3
125 = 5^3
625= 5^4
256 = 4^4
root 64 = 8
Substitute these values:
(4^3/5^3)(-2/3) + (5^4/4^4)^1/4 + 25/3*8
(4/5)^(-2) + (5/4) + 25/24
(5/4)^2 + 5/4 + 25/24
25/16 + 5/4 + 25/24
5/4* [ 5/4 + 1 + 5/6] = 5/4*[15+12+10/12]
= 5/4 * 37/12 = 185/48 = 3.85 (approx)
Answered by
2
Answer:
8.
(1)-(4)
3 + (256,-1/4+13)
125
625
(ii)Find the value of x: 3x – 2=4
Or
Factorise:(a+2b) +101(a+2b)+100
If (a+b+c=
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