Question

simplify (-6a^3b^5)(2a^2b^3)
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-18 x a^4 x b^8 x c^3





if you know pls answer ​

Answer 1

Answer:

$\frac{(-6a^3b^5)(2a^2b^3)}{-18*a^4*b^8*c^3}$ $=\frac{2a}{3c^3}$

Step-by-step explanation:

$\frac{(-6a^3b^5)(2a^2b^3)}{-18*a^4*b^8*c^3}$

$=\frac{2a^{(3+2)}b^{(5+3)}}{3*a^4*b^8*c^3}$  [∵$a^m.a^n = a^{(m+n)}$]

$=\frac{2a^{(5-4)}}{3c^3}$  [∵$\frac{a^m}{a^n} = a^{(m-n)}$]

$=\frac{2a}{3c^3}$

Answer 2

Answer:

hope it's helpful answer

Step-by-step explanation:

armyy