Math, asked by imteyazhaidry1121, 1 year ago

SIMPLIFY:(6x²-5)-{(4x²+3)+(2x²-8)}


amitnrw: 0 is answer
varalakshmiishwarya: 0 is the answer

Answers

Answered by jiitaalamrita
0

Answer: 0

Step-by-step explanation:(6x^2-5)-{(4x²+3)+(2x²-8)}

=(6x²-5)-{4x²+3+2x²-8}

=(6x²-5)-(6x²-5)

=6x²-5-6x²+5

=0

Answered by amitnrw
3

Answer:

Step-by-step explanation:

(6x^2-5)-{(4x²+3)+(2x²-8)}

at first we will open the ()bracket inside {} bracket

=(6x²-5)-{4x²+3+2x²-8}

now added 4x²+ 2x². and 3 + -8

=(6x²-5)-{6x²-5}

now opening the bracket {} as - is before bracket so sign inside bracket will change

=(6x²-5) -6x²+5

opening first bracket

= 6x²-5 - 6x²+5

now 6x²-6x² and 5-5

=0

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