Math, asked by tanvighadge17, 1 year ago

Simplify (7)1/5÷(7)1/3

Answers

Answered by mansukh1
66
hope it will help you
Attachments:

Lokeshkorampalli: i dont think the question is about indices. i think it is fractions
Answered by payalchatterje
2

Answer:

Simple form of given term is  {7}^{ -  \frac{2}{15} }

Step-by-step explanation:

Given, {7}^{ \frac{1}{5} }  \div  {7}^{ \frac{1}{3} }

This is a problem of power of indices,

 {7}^{ \frac{1}{5} }  \div  {7}^{ \frac{1}{3} }   \\ =  \frac{ {7}^{ \frac{1}{5} } }{ {7}^{ \frac{1}{3} } }   \\ =  {7}^{ \frac{1}{5}  -  \frac{1}{3} }  \\  =  {7}^{ \frac{3 - 5}{15} }   \\ =  {7}^{ \frac{ - 2}{15} }

Simple form given term is  {7}^{ -  \frac{2}{15} }

Here applied formula is

 {x}^{y}   \div  {x}^{z}  =  {x}^{y - z}

Some other formulas of power of indices,

 {x}^{0}  = 1 \\  {x}^{1}  = x \\  { {x}^{(y)} }^{(a)}  =  {x}^{ya}  \\  {x}^{ - 1}  =  \frac{1}{x}  \\  {x}^{ - 1}  =  \frac{1}{x}

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