Question

simplify. 7/2+ 61/8​

Answer 1

(28+61)/8=89/8

Hope it will help you

Answer 2

Answer:

$\dfrac{7}{2}+\dfrac{61}{8}=\dfrac{89}{8}\quad \left(\mathrm{Decimal:\quad }\:11.125\right)$

Step-by-step explanation:

$\dfrac{7}{2}+\dfrac{61}{8}$

$\mathrm{Least\:Common\:Multiplier\:of\:}2,\:8$

            $\bullet~~\mathrm{Prime\:factorization\:of\:}2:\quad 2$

            $\bullet~~\mathrm{Prime\:factorization\:of\:}8:\quad 2\cdot \:2\cdot \:2$

$\mathrm{Multiply\:each\:factor\:the\:greatest\:number\:of\:times\:it\:occurs\:in\:either\:}2\mathrm{\:or\:}8$

$=2\cdot \:2\cdot \:2$

$\mathrm{Multiply\:the\:numbers:}\:2\cdot \:2\cdot \:2=8$

$\mathrm{Adjust\:Fractions\:based\:on\:the\:LCM}$

$\mathrm{Multiply\:each\:numerator\:by\:the\:same\:amount\:needed\:to\:multiply\:its}$ $\mathrm{corresponding\:denominator\:to\:turn\:it\:into\:the\:LCM}\:8$

$\mathrm{For}\:\dfrac{7}{2}:\:\mathrm{multiply\:the\:denominator\:and\:numerator\:by\:}\:4$

$\dfrac{7}{2}=\dfrac{7\cdot \:4}{2\cdot \:4}=\dfrac{28}{8}$

$=\dfrac{28}{8}+\dfrac{61}{8}$

$\mathrm{Since\:the\:denominators\:are\:equal,\:combine\:the\:fractions}:\quad \dfrac{a}{c}\pm \dfrac{b}{c}=\dfrac{a\pm \:b}{c}$

$=\dfrac{28+61}{8}$

$\mathrm{Add\:the\:numbers:}\:28+61=89$

$=\dfrac{89}{8}$