simplify 7 root 48-root 27 - root 3
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Answered by
80
7√48-√27-√3
=7√16*3-√9*3-√3
=7*4√3-3√3-√3
=28√3-3√3-√3
=(28-3-1)√3
=24√3
Answered by
21
Answer:24√3
Step-by-step explanation:
7√48-√27-√3
expand the numbers in the roots
=7√3*16 - √9*3 - √3
now you can remove the perfect square out of the root symbol
=7*4√3 - 3√3 - √3
=28√3 - 3√3 - √3
=24√3
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