Math, asked by vicky2391, 8 months ago

Simplify 7x²(3x - 9) + 3 and find its values for x = 4 and x = 6​

Answers

Answered by StyIish01
129

Answer:

339 and 2271 !!

Step-by-step explanation:

when X = 4

➦ 7 (4)² (3(4)-9)+ 3

➦ 112 (12-9) + 3

➦ 112(3) + 3

➦ 336 +3 ➦ 339.

When X = 6

➦ 7(6)²(3(6)-9) + 3

➦ 252 (18-9) + 3

➦ 252(9) + 3

➦ 2268 + 3 ➦ 2271.

_______________________________

Answered by hukam0685
10

Simplified form of \bf 7 {x}^{2} (3x - 9) + 3 is \bf 21 {x}^{3}  - 63 {x}^{2}  + 3.

Value of polynomial at x= 4 is 339 and 2271 at x=6.

Given:

  • 7 {x}^{2} (3x - 9) + 3

To find:

  • Simplify the expression.
  • find its values for x = 4 and x = 6.

Solution:

Step 1:

Simplify the expression.

Open the bracket and simplify the expression.

7 {x}^{2} (3x - 9) + 3 \\

or

 = 7 {x}^{2} (3x) - 7 {x}^{2} (9) + 3 \\

or

 \bf 7 {x}^{2} (3x - 9) + 3= 21 {x}^{3}  - 63 {x}^{2}  + 3 \\

Step 2:

Find the value for x=4.

Put x= 4 and solve

21 {(4)}^{3}  - 63 {(4)}^{2}  + 3 \\

or

=21 \times 64 - 63 \times 16 + 3

or

 = 1344 - 1008 + 3 \\

or

 \bf 21 {(4)}^{3}  - 63 {(4)}^{2}  + 3= 339 \\

Step 3:

Find the value for x=6.

Put x= 6 and solve.

 21 {(6)}^{3}  - 63 {(6)}^{2}  + 3 \\

or

 = 21 \times 216 - 63 \times 36 + 3 \\

or

 = 4536 - 2268 + 3 \\

or

 \bf 21 {(6)}^{3}  - 63 {(6)}^{2}  + 3= 2271 \\

Thus,

Simplified form of \bf 7 {x}^{2} (3x - 9) + 3 is \bf 21 {x}^{3}  - 63 {x}^{2}  + 3.

Value of polynomial at x= 4 is 339 and 2271 at x=6.

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