Question

Simplify: 7x2 + x (x + y - 1) – (x - 1) (x - 2) = 0, what is the value of x?​

Answer 1

Answer:

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Step-by-step explanation:

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Answer 2

Answer:

7x×2x(x+y-1)-(x-1)(x-2)=

7x×2x(x+y-1)=(x-1)(x-2)

L.H.S. =R.H.S

7x×2x^2+2xy-2x=

7x×2x^2-2x+2xy=

7x×x+2xy=

7x^2+2xy.......(1)

R.H.S

(x-1)(x-2)=

x(x-2)-1(x-2)=

x^2-2x-x+2=

x^2-x+2=

x+2=

x= -2

put value of x in eq.no. (1)

7x^2+2xy

7×(-2)^2+2×(-2)×y=

7×4+(-4)×y=

28-4×y=

28-4y=

28=4y

28/4=y

7=y

so value of x= -2 , y=7