Question

simplify (8^1/3+27^1/3)
please help me anyone​

Answer 1

${8}^{ \frac{1}{3} } = 2, - 1 + \sqrt{ - 3} , - 1 - \sqrt{ - 3}$

${27}^{ \frac{1}{3} } = 3, \frac{ - 3}{2} + \frac{3 \sqrt{ - 3} }{2} , \frac{ - 3}{2} - \frac{3 \sqrt{ - 3} }{2}$

$\sf{8}^{ \frac{1}{3} } + {27}^{ \frac{1}{3} } = 5, \frac{1}{2} \pm \frac{3 \sqrt{ - 3} }{2} ,2 \pm \sqrt{ - 3} , - \frac{5}{2} \pm \frac{5 \sqrt{ - 3} }{2} , - \frac{5}{2} \pm \frac{ \sqrt{ - 3} }{2}$

And, considering only the real value

${8}^{ \frac{1}{3} } + {27}^{ \frac{1}{3} } = 5$