Math, asked by sheejajolly203, 8 months ago

simplify (81)^1/3÷(81)^1/12​

Answers

Answered by adityaranjan267
5

Answer:

3

Step-by-step explanation:

(81)^1/3÷(81)^1/12= 81^1/3-1/12

81^1/4= 3

Answered by ushmagaur
1

Answer:

The value of the expression (81)^{1/3}\div (81)^{1/12} is 3.

Step-by-step explanation:

Recall the laws of exponent,

(i) (a^m)^n=a^{mn}

(ii) a^ma^n=a^{m+n}

(iii) \frac{a^m}{a^n}=a^{m-n}

Step 1 of 2

Consider the given expression as follows:

(81)^{1/3}\div (81)^{1/12}

Using the property (iii) law of exponent, we get

(81)^{\frac{1}{3}-\frac{1}{12}  }

Simplify as follows:

(81)^{\frac{4-1}{12} }

(81)^{3/12}

(81)^{1/4} . . . . . (1)

Step 2 of 2

Prime factorisation of the number 81 is,

81=3\times 3\times 3\times 3

Rewrite the number 81 as follows:

81=3^4

Substitute the value 3^4 for 81 in the expression (1) as follows:

(81)^{1/4}=(3^4)^{1/4}

Using the property (i) of law of exponents, we get

(81)^{1/4}=(3)^4^{(\frac{1}{4} )}

Simplify as follows:

(81)^{1/4}=3^{4/4}

(81)^{1/4}=3^1

               =3

Final answer: Therefore, the value of the expression (81)^{1/3}\div (81)^{1/12} is 3.

#SPJ2

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