Question

simplify(81x²-90xy+25y²/9x-5y)​

Answer 1

Answer:

$\frac{81x^{2}-90xy+25y^{2}}{9x-5y}= 9x-5y$

Step-by-step explanation:

$\frac{81x^{2}-90xy+25y^{2}}{9x-5y}$

$=\frac{(9x)^{2}-2\times 9x\times 5y+(5y)^{2}}{(9x-5y)}$

$=\frac{(9x-5y)^{2}}{(9x-5y)}$

/* By algebraic identity:

a²-2ab+b² = (a-b)² */

$= 9x-5y$

Therefore,

$\frac{81x^{2}-90xy+25y^{2}}{9x-5y}= 9x-5y$

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