Question

simplify: 8th sum pls

Answer 1

(-1/2)3×_/256/81
(-1/8)×16/9
=-2/9

Answer 2

$\boxed{\boxed{\mathbf{\frac{-2}{9}}}}$
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$\underline{\underline{\Large\mathfrak{Solution :}}}$

$\mathsf{(- \frac{1}{2})^3 \times \sqrt{\frac{256}{81}}}$

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We Have To,

Take cube of $\mathsf{(- \frac{1}{2})}$

i.e $\mathsf{\frac{-1}{2} \times \frac{-1}{2} \times \frac{-1}{2} = - \frac{1}{8}}$

And,

Take square root of $\mathsf{\frac{16}{9}}$

i.e $\mathsf{\sqrt{\frac{256}{81} = \frac{16 \times 16}{9 \times 9}} = \frac{16}{9}}$

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Now,

$\mathsf{=> \frac{-1}{8} \times \frac{16}{9}}$

$\mathsf{=> \frac{-1}{8} \times \frac{16}{9}}$

$\mathsf{=> {-1} \times \frac{2}{9}}$

=> $\boxed{\mathsf{ \frac{-2}{9}}}$

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