Math, asked by achaithra852, 6 months ago

Simplify 9^1/3×27^1/2÷3^-1/6×3^1/3

Answers

Answered by Abishek011
1

Answer:

(3)^2×1/3×3^3×1/2÷3-1/6×3^1/3

3^2/3×3^3/2÷3-1/6×3^1/3

as base same we work on power

3^2/3+3/2÷3^-1/6+1/3

= 3^13/6÷3^1/6

=3^13/6-1/6

3^12 using x^n÷x^m=x^n-m

{plz click on thank you}

Answered by Vedikaditya
0

Step-by-step explanation:

Answer:

\frac{9^{\frac{1}{3}}\times27^{-\frac{1}{2}}}{3^{\frac{1}{6}}\times3^{-\frac{2}{3}}}=3^{\frac{-1}{3}}

3

6

1

×3

3

2

9

3

1

×27

2

1

=3

3

−1

Step-by-step explanation:

Given Expression: \frac{9^{\frac{1}{3}}\times27^{-\frac{1}{2}}}{3^{\frac{1}{6}}\times3^{-\frac{2}{3}}}

3

6

1

×3

3

2

9

3

1

×27

2

1

We have to simplify it,

Consider,

\frac{9^{\frac{1}{3}}\times27^{-\frac{1}{2}}}{3^{\frac{1}{6}}\times3^{-\frac{2}{3}}}

3

6

1

×3

3

2

9

3

1

×27

2

1

\implies\frac{(3^2)^{\frac{1}{3}}\times(3^3)^{-\frac{1}{2}}}{3^{\frac{1}{6}}\times3^{-\frac{2}{3}}}⟹

3

6

1

×3

3

2

(3

2

)

3

1

×(3

3

)

2

1

Now we use law of exponent, (x^a)^b=x^{a\times b}(x

a

)

b

=x

a×b

\implies\frac{3^{2\times{\frac{1}{3}}}\times3^{3\times{-\frac{1}{2}}}}{3^{\frac{1}{6}}\times3^{-\frac{2}{3}}}⟹

3

6

1

×3

3

2

3

3

1

×3

3×−

2

1

\implies\frac{3^{\frac{2}{3}}\times3^{\frac{-3}{2}}}{3^{\frac{1}{6}}\times3^{-\frac{2}{3}}}⟹

3

6

1

×3

3

2

3

3

2

×3

2

−3

We use another law of exponent, x^a\times x^b=x^{a+b}x

a

×x

b

=x

a+b

\implies\frac{3^{\frac{2}{3}+\frac{-3}{2}}}{3^{\frac{1}{6}+(-\frac{2}{3})}}⟹

3

6

1

+(−

3

2

)

3

3

2

+

2

−3

\implies\frac{3^{\frac{-5}{6}}}{3^{\frac{-1}{2}}}⟹

3

2

−1

3

6

−5

We use another law of exponent, \frac{x^a}{x^b}=x^{a-b}

x

b

x

a

=x

a−b

\implies3^{\frac{-5}{6}-\frac{-1}{2}}⟹3

6

−5

2

−1

\implies3^{\frac{-1}{3}}⟹3

3

−1

Therefore, \frac{9^{\frac{1}{3}}\times27^{-\frac{1}{2}}}{3^{\frac{1}{6}}\times3^{-\frac{2}{3}}}=3^{\frac{-1}{3}}

3

6

1

×3

3

2

9

3

1

×27

2

1

=3

3

−1

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