Question

simplify: 9-2√3x-x^2÷3-x^2

Answer 1

$\frac{9 - 2 \sqrt{3}x - x^2 }{3 - x^2}$

$\frac{-1(x^2 + 2 \sqrt{3}x - 9) }{( \sqrt{3})^2 - (x)^2 }$

$\frac{-1[x^2 + (3 \sqrt{3} - \sqrt{3})x - 9 }{( \sqrt{3}-x)( \sqrt{3} + x) }$

$\frac{-1[x^2 + 3 \sqrt{3}x - \sqrt{3}x - 9 ] }{( \sqrt{3}-x)( \sqrt{3}+x) }$

$\frac{-1[x(x + 3 \sqrt{3})- \sqrt{3}(x + 3 \sqrt{3}) }{( \sqrt{3}-x)( \sqrt{3}+x) }$

$\frac{(-1)(x + 3\sqrt{3}) (x - \sqrt{3}) }{( \sqrt{3}-x)( \sqrt{3} + x) }$


$\frac{(x + 3\sqrt{3}) ( \sqrt{3}- x) }{( \sqrt{3}-x)( \sqrt{3}+ x) }$

$\frac{x + 3 \sqrt{3} }{ \sqrt{3} + x}$


i hope this will help you



-by ABHAY