Question

simplify 9÷2 + (-4÷5) + (-5÷2) + 7÷5​

Answer 1

Answer:

2.6 is correct answer

please mark as brainest answer

Answer 2

Answer:

$\frac{13}{5}$

Step-by-step explanation:

We can rewrite the question as

   $\frac{9}{2} +(\frac{-4}{5}) + (\frac{-5}{2}) + \frac{7}{5}$

Upon rearranging the order of the numbers we get

⇒ $\frac{9}{2} + (\frac{-5}{2}) + (\frac{-4}{5})+\frac{7}{5}$

Since, the denominator of $\frac{9}{2}$ and $\frac{-5}{2}$, $\frac{-4}{5}$ and $\frac{7}{5}$ is the same we can write this as

⇒ $\frac{9+(-5)}{2} + \frac{(-4)+7}{5}$

⇒ $\frac{9-5}{2} + \frac{-4+7}{5}$

⇒ $\frac{4}{2} + \frac{3}{5}$

Since, the denominators of $\frac{4}{2}$ and $\frac{3}{5}$ is not the same, we'll take their LCM.

⇒ $L.C.M(2,5) = 10$

We multiply and divide $\frac{4}{2}$ by $5$; and multiply and divide $\frac{3}{5}$ by $2$

⇒ $\frac{4(5)}{2(5)} + \frac{3(2)}{5(2)}$

⇒ $\frac{20}{10} + \frac{6}{10}$

Now that the denominators are the same we can add them

⇒ $\frac{20+6}{10}$

⇒ $\frac{26}{10}$

We can further simplify this as

⇒ $\frac{13}{5}$