Question

simplify [9(64^1\3 + 125^1/3)^3]^1/4 plz explain

Answer 1

$\bigg[ 9 \bigg(64^{\frac{1}{3}} + 125^{\frac{1}{3}} \bigg)^3 \bigg]^{\frac{1}{4}}$

Rewrite 64 and 125 as exponents:

$\bigg[ 9 \bigg((4^3)^{\frac{1}{3}} + (5^3)^{\frac{1}{3}} \bigg)^3 \bigg]^{\frac{1}{4}}$

Evaluate the exponents:

$\bigg[ 9 \bigg(4 + 5\bigg)^3 \bigg]^{\frac{1}{4}}$

Add 4 and 5:

$\bigg[ 9 \bigg( 9 \bigg)^3 \bigg]^{\frac{1}{4}}$

Combine the 9s as exponents:

$\bigg[ 9^4 \bigg]^{\frac{1}{4}}$

Evaluate the exponents:

$9$

.

Answer: 9

Answer 2

Step-by-step explanation:

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