Question

simplify:(-90)+(-125)÷(-25)+95​

Answer 1

$\bf( - 90) + ( - 125) \div ( - 25) + 95 = 10$

Given:

• $( - 90) + ( - 125) \div ( - 25) + 95$

To find:

• Simplify the expression.

Solution:

Concept/Formula to be used:

• Apply BODMAS rule.

• B: Brackets

• O:of

• D:Divide

• M:Multiply

• A:Addition

• S: Subtraction

Step 1:

Simplify the expression.

Open the bracket first.

$= - 90+ ( - 125) \div ( - 25) + 95$

Now, according to the BODMAS rule, solve the division.

$- 90+ ( - 125) \div ( - 25) + 95 = - 90 + \frac{( - 125)}{( - 25)} + 95$

(-ve) signs of both numbers will be cancelled.

$= - 90 + 5+ 95$

Step 2:

Simplify the expression further.

Add and subtract the numbers.

$= - 90 + 100$

$\bf = 10$

Thus,

$\bf( - 90) + ( - 125) \div ( - 25) + 95 = 10$

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Answer 2

$\displaystyle \sf ( - 90) + ( - 125) \div ( - 25) + 95 = \bf \: 10$

Given :

$\displaystyle \sf ( - 90) + ( - 125) \div ( - 25) + 95$

To find :

To simplify the expression

Concept :

BODMAS rule :

B - Brackets

O - Order

D - Division

M - Multiplication

A - Addition

S - Subtraction.

Solution :

Step 1 of 2 :

Write down the given expression

Here the given expression is

$\displaystyle \sf ( - 90) + ( - 125) \div ( - 25) + 95$

Step 2 of 2 :

Simplify the given expression

$\displaystyle \sf ( - 90) + ( - 125) \div ( - 25) + 95$

$\displaystyle \sf = ( - 90) + \big[( - 125) \div ( - 25)\big] + 95$

$\displaystyle \sf = ( - 90) + 5 + 95 \: \: \bigg[Using \: BODMAS \: rule \bigg]$

$\displaystyle \sf = ( - 90) + 100 \: \: \bigg[Using \: BODMAS \: rule \bigg]$

$\displaystyle \sf =10 \: \: \bigg[Using \: BODMAS \: rule \bigg]$

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