Math, asked by zoyafathima562, 7 months ago

simplify a^-1/a^-1+b^-1 + a^-1/a^-1-b^-1

Answers

Answered by Anonymous
2

Step-by-step explanation:

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=(a+b)^-1.(a^-1+b^-1)

=1/(a+b) (1/a+1/b)

=1/a+b (b+a/ab) [LCM]

=(1/(a+b)) ((a+b)/ab) [(a+b) will get cut]

=1/ab

Answered by angel0220
0

Answer:

2

Step-by-step explanation:

we know that a^-1=1/a

b^-1=1/b

so,

(a^-1/a^-1) + (b^-1) +(a^-1/a^-1) -(b^-1)

= (a/a) +(1/b) +(a/a) -(1/b)

= 1+1/b+1-1/b=2+1/b-1/b

=2

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