Math, asked by zoyafathima562, 7 months ago

simplify a^-1/a^-1+b^-1 + a^-1/a^-1-b^-1

Answers

Answered by Anonymous
4

Step-by-step explanation:

 \huge\underline\mathfrak{\pink{AnsWeR }}

=1/a×ab /b+a+ 1/a×ab /b-a

=b /b+a+b /b-a

take the LCM of the denominator and so it becomes:

=b(b-a)/(b+a)(b-a)+b(b+a)/(b-a)(b+a)

=b2 -ab /b2 -a2 +b2 +ab /b2 -a2

=b2 -ab +b2 +ab /b2 -a2

=b2+b2/b2-a2

=2b2/b2 -a2 ==== RHS (Right Hand Side)

Step-by-step explanation:

Answered by ItzDeadDeal
0

\huge\underline\mathfrak{\blue{AnsWeR }} </p><p>

=1/a×ab /b+a+ 1/a×ab /b-a

=b /b+a+b /b-a

take the LCM of the denominator and so it becomes:

=b(b-a)/(b+a)(b-a)+b(b+a)/(b-a)(b+a)

=b2 -ab /b2 -a2 +b2 +ab /b2 -a2

=b2 -ab +b2 +ab /b2 -a2

=b2+b2/b2-a2

=2b2/b2 -a2 ==== RHS (Right Hand Side)

Step-by-step explanation:

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