Question

SIMPLIFY
a....10^2(10+10^-2)
b....(5+5^-1)(5-5^-1)
c....(5^-1-7^-1)^-1
d....[(2/3)^-1 - (1/2)^-1]^-1​
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Answer 1

Answer:

1) 1001

2) $24 \frac{24}{25}$ or 24.96

3) $17 \frac{1}{2}$ or 17.5

4) -2

Step-by-step explanation:

1) $10^{2} (10 + 10^{ - 2} )$

we know, ${x}^{-n} = \frac{1}{x}$

therefore,

$= {10}^{2} (10 + \frac{1}{100} )$

$= {10}^{2} \times \frac{1001}{100}$

$= 10^{2} \times \frac{1001}{ {10}^{2} }$

$= 1001$

2) $(5 + {5}^{ - 1} )(5 - {5}^{ - 1} )$

we know, ${x}^{-n} = \frac{1}{x}$

therefore,

$= (5 + \frac{1}{5} )(5 - \frac{1}{5} )$

$= \frac{26}{5} \times \frac{24}{5}$

$= \frac{624}{25}$

$= 24 \frac{24}{25}$

or,

$= 24.96$

3) ${( {5}^{ - 1} - {7}^{ - 1} )}^{ - 1}$

we know, ${x}^{-n} = \frac{1}{x}$

therefore,

$={ ( \frac{1}{5} - \frac{1}{7} )}^{ - 1}$

$= ( \frac{7 - 5}{35} )^{ - 1}$

$= ( \frac{2}{35} )^{ - 1}$

we know, any expression raised to the power -1 is equal to it's reciprocal.

$= ( \frac{35}{2} )$

$= 17 \frac{1}{2}$

or,

$= 17.5$

4) ${(( \frac{2}{3} )^{ - 1} - ({ \frac{1}{2} )}^{ - 1} )}^{ - 1}$

we know, ${x}^{-n} = \frac{1}{x}$

also, any expression raised to the power -1 is equal to it's reciprocal.

therefore,

$= (( \frac{2}{3}) - 2)$

$= \frac{2 - 4}{2}$

$= - 2$

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Answer 2

Woh vrinda bhi nhi deti hai aur nahi gunjan Deri hai mujhe 8A-3 mein se kisi aur ka number lena hoga kya tune kabhi dusre section ki ladkiyon se koi work nhi Liya hai kya please tell me after this period