Simplify (a 2 -b 2 ) 3 +(b 2 -c 2 ) 3 +(c 2 -a 2 ) 3 divided by (a-b) 3 +(b-c) 3 +(c-a) 3
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Answered by
327
Hi ,
*******************************************
We know that ,
If x + y + z = 0
then
x³ + y³ + z³ = 3xyz
*******************************************
Now ,
i ) Let x = a² - b² ,
y = b² - c²
z = c² - a²
x + y + z = a² - b² + b² - c² + c² - a²
= 0
Therefore ,
( a² - b² )³ + ( b² - c² )³ + ( c² - a² )³
= 3( a² - b² )( b² - c² )( c² - a² ) ---( 1 )
Similarly ,
ii ) ( a - b )³ + ( b - c )³ + ( c - a )³
= 3( a - b )( b - c )( c - a ) ----( 2 )
Now ,
( 1 ) ÷ ( 2 )
=[3(a²-b²)(b²-c²)(c²-a²)]/[3(a-b)(b-c)(c-a)]
= ( a + b )( b + c )( c + a )
I hope this helps you.
: )
*******************************************
We know that ,
If x + y + z = 0
then
x³ + y³ + z³ = 3xyz
*******************************************
Now ,
i ) Let x = a² - b² ,
y = b² - c²
z = c² - a²
x + y + z = a² - b² + b² - c² + c² - a²
= 0
Therefore ,
( a² - b² )³ + ( b² - c² )³ + ( c² - a² )³
= 3( a² - b² )( b² - c² )( c² - a² ) ---( 1 )
Similarly ,
ii ) ( a - b )³ + ( b - c )³ + ( c - a )³
= 3( a - b )( b - c )( c - a ) ----( 2 )
Now ,
( 1 ) ÷ ( 2 )
=[3(a²-b²)(b²-c²)(c²-a²)]/[3(a-b)(b-c)(c-a)]
= ( a + b )( b + c )( c + a )
I hope this helps you.
: )
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