Math, asked by kumarirashmi1098, 1 month ago

simplify (a^2+b^2)(a^2+b^2)-(a^2-b^2)(a^2-b^2)​

Answers

Answered by tharunv500
1

=(a+b)²×(a+b)²-(a-b)²×(a-b)²

={(a²+b²+2ab)×(a²+b²+2ab)}-{(a²+b²-2ab)×(a²+b²-2ab)}

=(a⁴+b⁴+4ab²)-(a⁴+b⁴-4ab²)

=a⁴+b⁴+4ab²-a⁴-b⁴+4ab²

0+0+8ab²

=8ab²

Answered by thillaivanan20073
0

Answer:

4a²+2b²

Step-by-step explanation:

given that

(a²+b²)(a²+b²)-(a²-b²)(a²-b²)

(a²+b²)²-(a²-b²)²

by a+b and a-b the whole square formula

(a²)²+(b²)²+2×a²b²-(a²)²+(b²)²-2a²b²

(a⁴+b⁴+2a²b²)-(a⁴+b⁴-2a²b²)

a⁴+b⁴+2a⁴b⁴-a⁴-b⁴+2a²b²

a⁴-a⁴+b⁴-b⁴+2a²b²+2a²b²

2(2a²+b²)

4a²+2b²

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