Math, asked by Mahakyadav14, 5 months ago

Simplify:a^2(b^2-c^2)+b^2(c^2-a^2)+c^2(a^2-b^2)
Give me full solution.please
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Answers

Answered by Aking47
1

=a^2(b^2-c^2)+b^2(c^2-a^2)+c^2(a^2-b^2)

=a^2(b^2-c^2)+b^2(c^2-a^2)+c^2(a^2-b^2)=(a^2*b^2-a^2*c^2)+(b^2*c^2-a^2*b^2)+(c^2*a^2-c^2*b^2)

=a^2(b^2-c^2)+b^2(c^2-a^2)+c^2(a^2-b^2)=(a^2*b^2-a^2*c^2)+(b^2*c^2-a^2*b^2)+(c^2*a^2-c^2*b^2)BY CANCELLING THE -+ TERMS WE AQUIRE ANSWER AS 0.

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