Question

Simplify : a – (2a – b) – 3b – (a – 3b)​

Answer 1

Answer:

Step-by-step explanation:

LHS =(2a+3b)(a−b)

=2a(a−b)+3b(a−b)

=2a×a−2a×b+3b×a−3b×b

=2a  2  −2ab+3ab−3b  2

 

=2a  2  +ab−3b  2

 

Thus, (2a+3b)(a−b)



=2a  2  −3b  2

, but (2a+3b)(a−b)=2a  2  +ab−3b  2

 is the correct statement.

Answer 2

In context of question asked,

We have to determine the value of the expression.

As per question,

We have,

$a-(2a-b)- 3b-(a-3b)$

So, for determining the value of expression, we will remove the bracket parts and then determine the value of expression by separating the like terms on one side.

So, we will get,

$a-2a+b- 3b-a+3b\\=>a-2a-a +b-3b+3b\\=>a-3a+4b-3b\\=>-2a+b$

Hence, value of the expression will be (-2a +b)