simplify :(a+2b)³+(a+2b)²(a-2b) +3(a-2b)(a-2b) ²+(a-2b) ³
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Answer:
4b(3a2+4b2
Step-by-step explanation:
Remembering that a difference of cubes can be factored:
a3−b3=(a−b)(a2+ab+b2),
then:
(a+2b)3−(a−2b)3=
=[(a+2b)−(a−2b)][(a+2b)2+(a+2b)(a−2b)+(a−2b)2]=
=(a+2b−a+2b)(a2+4ab+4b2+a2−4b2+a2−4ab+4b2]=
=4b(3a2+4b2).
But, in this case, there is a faster and easier way:
(a+2b)3−(a−2b)
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