Math, asked by tanujasharma00, 8 months ago

simplify [a^3 b^2/a^3 b^3]-3

Answers

Answered by Anonymous
0

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 =  {( {a}^{3}  \times  \frac{ {b}^{2} }{ {a}^{3} }  \times {b}^{3}  )}^{ - 3}  \\  = ( { {b}^{2 + 3} })^{ - 3}  \\  =  {b}^{ - 15} ✔️✔️✔️

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Answered by MissHarshitaV
3

Answer:

a³−

b

3

=

(

a

b

)

(

a

2

+

a

b

+

b

2

)

where

a

=

a

and

b

=

b

.

(

a

b

)

(

a

2

+

a

b

+

b

2

)

a

2

b

2

Since both terms are perfect squares, factor using the difference of squares formula,

a

2

b

2

=

(

a

+

b

)

(

a

b

)

where

a

=

a

and

b

=

b

.

(

a

b

)

(

a

2

+

a

b

+

b

2

)

(

a

+

b

)

(

a

b

)

Cancel the common

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