Question

simplify (a) [4^0 - (2/3+1/3)](-192)^5​

Answer 1

Answer:is 0

Step-by-step explanation:

first (4^0-(3/3) (-192)5

Answer 2

Answer:

0

Step-by-step explanation:

Given :- The given expression is  [ 4^0 - (2/3 + 1/3) ] (-192)^5​ .

To find :- Value of [ 4^0 - (2/3 + 1/3) ] (-192)^5​

Solution :-

We know that, when 0 is raised to the power of any number then it always evaluates to 1.

Odd number to the power of any negative number gives a negative number.

The given expression is  [ 4^0 - (2/3 + 1/3) ] (-192)^5​

= [ $4^{0}$ - (2/3 + 1/3) ] $( -192)^{5}$

= [ 1 - ( (2 + 1 )/3) ] ( -192 )

= [ 1 - (3/3)] ( -192 )

= [ 1 - 1 ] ( -192 )

= 0 × ( -192 )

= 0

Therefore, [ 4^0 - (2/3 + 1/3) ] (-192)^5​  = 0.

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