Simplify: a(a+b^2+c)- b^2 (a+b+c)–c(a+b^2 )
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16
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(ab+bc)2−2ab2c
Using,
(a+b)2=a2+2ab+b2 we get,
=(ab)2+2(ab)(bc)+(bc)2−2ab2c
=a2b2+2ab2c+b2c2−2ab2c
=a2b2+b2c2
Answered by
49
➛a(a+b²+c)- b²(a+b+c)–c(a+b²)
= a² + ab² + ac - ab² + b³ + b²c -ac - b²c
= a² + b³
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