Question

simplify a(a² + a + 1 ) + 5 and find it's value for (í) a = -1.​

Answer 1

Answer:

Given, a = ( - 1 )

➡ substituting the value in the expression

$a( {a}^{2} + a + 1) + 5 \\ \\ = {a}^{3} + {a}^{2} + a + 5 \\ \\ = ( - 1) ^{3} + {( - 1)}^{2} + ( - 1) + 5 \\ \\ = - 1 + (1) - 1 + 5 \\ \\ = - 1 + 1 - 1 + 5 \\ \\ = - 1 - 1 + 1 + 5 \\ \\ = - 2 + 6 \\ \\ = 4$

# keep smiling ☺

Answer 2

Solution

$\sf\pink{⟶}$ Firstly, we have to simplify the given Equation.

⠀

$\tt:\implies\: \: \: \: \: \: \: \: {a(a^2 + a + 1) + 5}$

⠀

$\tt:\implies\: \: \: \: \: \: \: \: {a^3 + a^2 + a + 5}$

⠀

$\sf\pink{⟶}$ Now according to the question, we have to put the value of a = -1.

⠀

$\tt:\implies\: \: \: \: \: \: \: \: {(-1)^3 + (-1)^2 + (-1) + 5}$

⠀

$\tt:\implies\: \: \: \: \: \: \: \: {-1 + 1 - 1 + 5}$

⠀

$\tt:\implies\: \: \: \: \: \: \: \: {0 + 4}$

⠀

$\tt:\implies\: \: \: \: \: \: \: \: {4}$

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