Question

simplify :a(a2+a+1)+5 and find its value for (1)a=0,(2)a=1,(3)a=-1​

Answer 1

Given: The equation a (a^2 + a + 1 ) + 5

To find: Value of equation at point (1)a=0, (2) a=1, (3) a=-1​

Solution:

• Now we have given the equation as a (a^2 + a + 1 ) + 5, so putting values one by one, we get:

• (1)a=0

               a (a^2 + a + 1 ) + 5 = 0(0^2 + 0 + 1) + 5

               = 0 + 5 = 5

• (2) a=1

               a (a^2 + a + 1 ) + 5  = 1(1^2 + 1 + 1) + 5

               = 3 + 5 = 8

• (3) a=-1​

               a (a^2 + a + 1 ) + 5 = -1(-1^2 - 1 + 1) + 5

               = -1 + 5 = 4

Answer:

          So the value of a (a^2 + a + 1 ) + 5 at point (1)a=0 is 5, (2) a=1 is 8 and (3) a=-1​ is 4.

Answer 2

Answer:

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