Question

Simplify (a - b) (2a²-3ab+b²) and find its value for a = 3, b = 2​

Answer 1

Answer:

4

Step-by-step explanation:

(a-b) (2a^2-3ab+b^2)

(3-2)(2×3^2-3×3×2+2^2)

(1)(18-18+4)

(1)(4)

4

I hope this answer is correct ❤

Answer 2

• We have to evaluate the above expression by using the given data.

              Given data:-$a=3, b=2.$

              To find:-Value of the $(a-b)(2a^{2} -3ab+b^{2}) .$

              Solution:-

• To solve the above equation we will follow the BODMAS rule.

• BODMAS is an order of mathematic operations.

• BODMAS rule is to be followed while solving expressions in mathematics. It stands for,

           B= bracket

            O= order of power or rules

            D= division

            M= multiplication

            A= addition

            S= subtraction

      Now put the value , and  in the given equation

       $(a-b)(2a^{2} -3ab+b^{2}) \\\Rightarrow (3-2)(2\times(3)^{2} -3\times(3)\times(2)+2^{2})\\\Rightarrow (1)(2\times9-18+4)\\\Rightarrow 18-18+4\\\Rightarrow 4.$

     Hence we will get the value $4.$