Math, asked by sarthak454833, 10 months ago

Simplify: (a + b)(a - b) +(b+c)(b -c)+(c + a)(c-a)​

Answers

Answered by priyaMajumdar
2

Answer:

(a+b)(a - b) + (b+c)(b - c) + (c+a)(c - a)

a² - b² + b² - c² + c² - a²

0

Step-by-step explanation:

Mark me brainlist......✌✌✌✌✌✌✌✌

Answered by lambatehanmant72
0

Answer:

(a+b)(a-b)+(b+c)(b-c)+(c+a)(c-a)=a²-b²+b²-c²+c²-a²

{®(x+y)(x-y)=x²-y²}

=0

(a+b)(a-b)+(b+c)(b-c)+(c+a)(c-a)=0

Similar questions