Question

simplify (a+b+c)²-(a-b-c)²​

Answer 1

Answer:

\sqrt{(1-1)^2 + (6-2)^2} = \sqrt{0^2 + 4^2} = \sqrt{0 + 16} = \sqrt{16} = 4

(1−1)

2

+(6−2)

2

=

0

2

+4

2

=

0+16

=

16

=4

Answer 2

= (a+b+c)² - [(a-b-c)]

= (a+b+c) (a+b+c) - [(a-b-c) (a-b-c)]

= a²+b²+c²+2ab+2bc+2ca-[a²+b²+c²-2ab-2bc-2ac]

= a²+b²+c²+2ab+2bc+2ac - a²-b²-c²+2ab+2bc+2ac

= 4ab+4bc+4ac

= 4(ab+bc+ac).