simplify
(a + b +c)²-(a-b-c)²
nehasharma16:
The right answer is zero.
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Let (a+b+c) =p
And (a-b-c) =q hence
(a+b+c)^2-(a-b-c)^2 = p^2-q^2
= (p+q) (p-q)
Hence
(a+b+c+a-b-c) (a+b+c-a+b+c)
= 2a*2(b+c)
=4a(b+c)
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