Math, asked by TanujaBalodhi, 1 year ago

simplify
(a + b +c)²-(a-b-c)²​


nehasharma16: The right answer is zero.
Anonymous: 2(a+b+c)
Anonymous: sorry
nehasharma16: It's ok
Anonymous: 4(ab+ac)
hariprasath1517: => 4 (ab+ac)= 4a (b+c)

Answers

Answered by aryan3664
0

Let (a+b+c) =p

And (a-b-c) =q hence

(a+b+c)^2-(a-b-c)^2 = p^2-q^2

= (p+q) (p-q)

Hence

(a+b+c+a-b-c) (a+b+c-a+b+c)

= 2a*2(b+c)

=4a(b+c)


aryan3664: mark me as brainalist when you got ri8 amswer
Answered by udaykumar92
0
(a + b + c) {}^{2} - (a - b - c) {}^{2}

(a {}^{2} + b {}^{2} + c {}^{2} + 2ab + 2bc + 2ca) - (a {}^{2} + b {}^{2} + c {}^{2} + 2ab - 2bc + 2ca)

 +4bc
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