Question

Simplify (a-b+c)2 + (b-c+a)2 + 2(a-b+c)(b-c+a).​

Answer 1

Answer:

4a²

Step-by-step explanation:

(a-b+c)2+(b-c+a)²+2(a-b+c)(b-c+a)

= [(a-b+c)+(b-c+a)]²

/* By algebraic identity: x²+y²+2xy = (x+y)² */

= (a-b+c+b-c+a)²

= (2a)²

= 4a²

Therefore,

(a-b+c)²+(b-c+a)²+2 (a-b+c)(b-c+a)= 4a²