simplify (a+b-c) (a-b+c)
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Answer:
(a+b-c)(a-b+c) = a²-b²-c²+2bc
Step-by-step explanation:
(a+b-c)(a-b+c)
= [a+(b-c)][a-(b-c)]
= a²-(b-c)²
/* By algebraic identity:
(x+y)(x-y) = x²-y² */
= a² - (b²-2bc+c²)
/* By algebraic identity:
(x-y)² = x²-2xy+y² */
= a²-b²+2bc-c²
= a²-b²-c²+2bc
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